I am trying to pull out the all characters after the second space in a column. How do I do this? I don't understand substring and charindex.
DECLARE @a varchar(20)='1 space 2 space 3 space'; SELECT STUFF(@a,1,CHARINDEX(' ',@a,CHARINDEX(' ',@a)+1), '');
Substitute your column/variable/expression where @a appears.
STUFF() replaces a segment of text at a start and end position, in this case, 2 CHARINDEX() functions. CHARINDEX() returns the position where the first text appears in the second.
You really should take the time to learn about SUBSTRING and CHARINDEX... they're a part of the fundamentals of the SQL language and you won't get far in life without them,