Finding the tree structure

I have the following table:

SELECT 'A' as Item, '1' as Version, 0 as Counter, '01-01-2011' as CreatedDate UNION ALL
SELECT 'A' as Item, '1.1' as Version, 1 as Counter, '01-02-2011' as CreatedDate UNION ALL
SELECT 'A' as Item, '1.2' as Version, 2 as Counter, '01-03-2011' as CreatedDate UNION ALL
SELECT 'B' as Item, '1.2' as Version, 0 as Counter, '01-01-2011' as CreatedDate UNION ALL
SELECT 'B' as Item, '2' as Version, 1 as Counter, '01-10-2011' as CreatedDate UNION ALL
SELECT 'C' as Item, '1.5' as Version, 0 as Counter, '05-03-2011' as CreatedDate UNION ALL
SELECT 'C' as Item, '2.5' as Version, 1 as Counter, '05-04-2011' as CreatedDate UNION ALL
SELECT 'C' as Item, '3' as Version, 2 as Counter, '05-05-2011' as CreatedDate UNION ALL
SELECT 'C' as Item, '2' as Version, 3 as Counter, '06-01-2011' as CreatedDate UNION ALL
SELECT 'D' as Item, '1.3' as Version, 0 as Counter, '01-10-2011' as CreatedDate UNION ALL
SELECT 'D' as Item, '1.2' as Version, 1 as Counter, '03-10-2011' as CreatedDate UNION ALL
SELECT 'D' as Item, '3' as Version, 2 as Counter, '04-10-2011' as CreatedDate
I want to write a script where if a user enters the version number, then the output should show all the upward and downward nodes..e.g. if a user selects '1.2' version then following should be the output

http://imgur.com/a2SxnAV

Can someone please help me with this?

Thank you in advance

Your gave an example but the output is not shown here, so it is difficult to know what your want.

Please try with the below query and revert if it is not fulfill your requirement
select *
from #table a
left outer join #table b
on a.Item = b.Item
and a.version< b.version
where a.version=1.2

Thank you for your efforts mate..thats the start I wanted