I currently have a simple select query
Select IDColumn,Column1,column2
from Table
Output :

IDColumn Column1 Column2

OM One Monday
TT Two Tuesday
TW Three Wednesday
FT Four Thursday
FF Five Friday
SS Six Saturday

I would like the desired ouput to be that each row takes 3 unique ID columns before creating a second row
Desired output
IDColumn Column1 Column2 Column3 Column 4 Column 5 Column 6 Column 7 Column 8
OM One Monday TT Two Tuesday TT Three Wednesday
FT Four Thursday FF Five Friday SS Six Saturday

A note: the data returned does not have to be in any particular order.So if Wednesday is first that is fine

Insert INTO Weekdaystst Values('XX', 'Seven','Sunday')

SELECT
MAX(CASE WHEN row_num % 3 = 1 THEN ID END) AS ID1,
MAX(CASE WHEN row_num % 3 = 1 THEN Column1 END) AS Column1,
MAX(CASE WHEN row_num % 3 = 1 THEN Column2 END) AS Column2,
MAX(CASE WHEN row_num % 3 = 2 THEN ID END) AS ID2,
MAX(CASE WHEN row_num % 3 = 2 THEN Column1 END) AS Column3,
MAX(CASE WHEN row_num % 3 = 2 THEN Column2 END) AS Column4,
MAX(CASE WHEN row_num % 3 = 0 THEN ID END) AS ID3,
MAX(CASE WHEN row_num % 3 = 0 THEN Column1 END) AS Column5,
MAX(CASE WHEN row_num % 3 = 0 THEN Column2 END) AS Column6
FROM (
SELECT *, ROW_NUMBER() OVER(ORDER BY ID) AS row_num
FROM dbo.Weekdaystst
) AS row_nums
GROUP BY (row_num - 1) / 3